**IMPORTANT INFORMATION: TEST 2 will be ON CAMPUS/IN PERSON starting Fall 2023 semester.**

This test is for students wishing to enrol in courses covering

* pre-calculus algebra at about the Grade 12 level, like MATH 1152 or 1170

* calculus, like MATH 1171, or 1173

* life science calculus, like MATH 1175

* business calculus, like MATH 1174

This test is multiple choice and consists of two parts. Part 1 consists of approx. 16 questions. Part 2 consists of approx. 15 questions. Each part is allotted 50 minutes. All students should write as much of the test as they can. Generally, the test questions are ordered by increasing level of difficulty. Entry into MATH 1152 or 1170 will be determined mainly by performance on the Part 1 of the MDT. Entry into MATH 1171, 1173, 1174 or 1175 will be determined by performance on both Part 1 and Part 2.

Although we feel it is not necessary for this test, students are permitted to use a scientific or business calculator. Calculators with graphing, programming, algebraic, or text retrieval capabilities **are not permitted**.

### Sample Questions from Math Test 2

**Part 1 (Algebra, functions, triangle trig, word problems)**

If x - 3( 2 - x ) = 2( x + 1 ) - 3, then x =

- (A)
^{-5}/_{3} - (B)
^{-4}/_{3} - (C)
^{-5}/_{4} - (D)
^{3}/_{2} - (E)
^{5}/_{2}

If a car travels m kilometres in h hours, how much time will it take to travel M kilometres?

- (A)
^{M}/_{m}hours - (B)
^{mh}/_{M}hours - (C)
^{M}/_{h}hours - (D)
^{Mh}/_{m}hours - (E)
^{Mm}/_{h}hours

**Part 2 (algebra, graphs, functions, trig, logs, word problems)**

Evaluate log_{3}( 27 ) + log_{2}( ^{1}/_{8} ) - log_{5}( 5 )

- (A)
^{7}/_{3} - (B) -1
- (C) 0
- (D)
^{-1}/_{3} - (E) None of these

Find the equation of the line containing the point ( 1, -2 ) and perpendicular to the line containing the points ( 1, 5 ) and ( 3, 2 ).

- (A) 3x - 2y - 7 = 0
- (B) 2x + 3y + 4 = 0
- (C) 2x - 3y - 8 = 0
- (D) 3x + 2y + 1 = 0
- (E) 2x - 3y + 8 = 0

*The answers to the sample questions are (E) ^{5}/_{2}, (D) ^{Mh}/_{m}, (B) - 1, and (C) 2x - 3y - 8 = 0*